English 中文(简体)
使用python确定相对复杂的数学表达式中的分子和分母
原标题:determining numerator and denominator in a relatively complex mathematical expression using python

我正在尝试将计算器输入转换为LaTeX。如果用户输入以下内容:

(3x^(x+(5/x)+(x/33))+y)/(32 + 5)

我必须将其转换为:

frac{3x^(x+frac{5}{x}+frac{x}{33})+y}{32 + 5x}

然而,我在确定分子何时开始和结束时遇到了问题。有什么建议吗?

最佳回答

已存在用于此类转换的包:Py2Tex公司

如果您想重用此包,可以使用py2tex.Interpret类来实现这一点。

问题回答

看看编译器

compiler.parse( (3*x**(x+(5/x)+(x/33))+y)/(32 + 5) )

退货

Module(None, Stmt([Discard(Div((Add((Mul((Const(3), Power((Name( x ), Add((Add((Name( x ), Div((Const(5), Name( x ))))), Div((Name( x ), Const(33))))))))), Name( y ))), Add((Const(32), Const(5))))))]))

其可以更容易地转换为LaTeX代码。您必须编写方法,以递归方式处理每个代码(Div、Add、Const、Name、Power…)及其参数,并返回适当的LateX代码。

如果你想使用问题的确切语法,那么你可以写计算器的解析器

#!/usr/bin/env python
from operator import add, div, mul, sub

from lepl  import Any, Delayed, Digit, Drop, DroppedSpace, Eos
from sympy import Symbol, latex, pprint

def Power(tokens):
    """x**(y**z)"""
    return reduce(lambda p, b: pow(b, p), reversed(tokens))

def Arithm(tokens):
    """(x op1 y) op2 z ..."""
    OP = {  * : mul,  / : div,  + : add,  - : sub, }
    tokens = iter(tokens)
    a = next(tokens)
    for op, b in zip(tokens, tokens):
        a = OP[op](a, b)
    return a

def makeparser():
    expr = Delayed()
    number = Digit()[1:,...] >> int # d+
    symbol = Any( xyz ) >> (lambda x: Symbol(bytes(x))) # unicode -> str
    muldiv_op = Any( */ )[:1] > (lambda x: x[0] if x else  * ) # xy -> x*y
    power_op = Drop( ^ ) | Drop( ** ) # both stand for pow(x, y)

    with DroppedSpace(): # ignore spaces
        term = number | symbol | Drop( ( ) & expr & Drop( ) )
        power   = term & (power_op  & term)[:] > Power
        factor = power & (muldiv_op & power)[:] > Arithm
        expr += factor & (Any( -+ ) & factor)[:] > Arithm
        line = expr & Eos()
    return line.get_parse()

parse = makeparser()
[expr] = parse( (3x^(x+(5/x)+(x/33))+y)/(32 + 5) )
pprint(expr)
print(latex(expr))

Output

        34⋅x   5
        ──── + ─
         33    x
y    3⋅x        
── + ───────────
37        37    
$frac{1}{37} y + frac{3}{37} x^{frac{34}{33} x + frac{5}{x}}$

一般来说,最好使用Python等现有语言的语法。





相关问题
Can Django models use MySQL functions?

Is there a way to force Django models to pass a field to a MySQL function every time the model data is read or loaded? To clarify what I mean in SQL, I want the Django model to produce something like ...

An enterprise scheduler for python (like quartz)

I am looking for an enterprise tasks scheduler for python, like quartz is for Java. Requirements: Persistent: if the process restarts or the machine restarts, then all the jobs must stay there and ...

How to remove unique, then duplicate dictionaries in a list?

Given the following list that contains some duplicate and some unique dictionaries, what is the best method to remove unique dictionaries first, then reduce the duplicate dictionaries to single ...

What is suggested seed value to use with random.seed()?

Simple enough question: I m using python random module to generate random integers. I want to know what is the suggested value to use with the random.seed() function? Currently I am letting this ...

How can I make the PyDev editor selectively ignore errors?

I m using PyDev under Eclipse to write some Jython code. I ve got numerous instances where I need to do something like this: import com.work.project.component.client.Interface.ISubInterface as ...

How do I profile `paster serve` s startup time?

Python s paster serve app.ini is taking longer than I would like to be ready for the first request. I know how to profile requests with middleware, but how do I profile the initialization time? I ...

Pragmatically adding give-aways/freebies to an online store

Our business currently has an online store and recently we ve been offering free specials to our customers. Right now, we simply display the special and give the buyer a notice stating we will add the ...

Converting Dictionary to List? [duplicate]

I m trying to convert a Python dictionary into a Python list, in order to perform some calculations. #My dictionary dict = {} dict[ Capital ]="London" dict[ Food ]="Fish&Chips" dict[ 2012 ]="...

热门标签