Question

Is there a way to compare 2 different lists. Specifically, I want to compare if the first 2 alphabets in the first list exist as the first 2 alphabets in the second list. Example list1=[ dog , cat , chicken ] list2=[ drew , car , table ] So I want to know if the first 2 alphabets in each of the list1 is also the first 2 alphabets in each of list 2.

Answer 1

它非常直截了当。将这两个清单合在一起,从每个清单中获取相应词语,然后对其进行比较,以确保所有语文都符合你们的标准。

>>> list1=[ dog , cat , chicken ]
>>> list2=[ drew , car , table ]
>>> all(x[:2] == y[:2] for x, y in zip(list1, list2))
False

Answer 2

我们可以同时利用zip()的功能,同时在两个名单上公布这些数值,同时在一旁边使用插座标语,以比较每个乳头两种特性:

list_a = [ dog ,  cat ,  chicken ]
list_b = [ drew ,  car ,  table ]

all_match = True
for word_a, word_b in zip(list_a, list_b):
    if word_a[:2] != word_b[:2]:
        print(f The following words do not match in their first two characters: {word_a} - {word_b} )
        all_match = False
        break
    
if all_match:
    print( All word pairs match in their first two characters. )

Edit: Seeing that you want to get the results as a list of boolean values, an easy modification to the above is:

list_a = [ dog ,  cat ,  chicken ]
list_b = [ drew ,  car ,  table ]
results = []

for word_a, word_b in zip(list_a, list_b):
    results.append(word_a[:2] == word_b[:2])

采用list comprehension :

list_a = [ dog ,  cat ,  chicken ]
list_b = [ drew ,  car ,  table ]

results = [a[:2] == b[:2] for (a, b) in zip(list_a, list_b)]

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