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如何通过地方变量,从铁路3号中的应用布局中排出一部分?
原标题:How to pass local variable to partial from application layout in rails 3?

我有多种变量,需要在所有控制人员中加以使用。 在布道上显示最新消息。

我在申请中创建这些控制器。

@hq_news_item = NewsItem.where(:branch_code => "CORP").first
@branch_news_item = NewsItem.where(:branch_code => "MN").first

In my layouts/application.html.haml

= render :partial => "layouts/footer_news"  , :hq_news_item => @hq_news_item, :branch_news_item => @branch_news_item

然后,在我的布局/脚踏上新闻 我这样说:

= hq_news_item.title
= hq_news_item.author.name
... etc

这里,无论我做什么,它都说,“hq_news”项目没有部分界定。

我的所有其他部分都做了罚款。 我认为,它必须处理的是,它没有提出看法。 无法找到任何有意义的东西。

任何想法?

谢谢。

最佳回答

我认为,你们需要将变量作为局部变量加以部分化:

= render :partial => "layouts/footer_news", :locals => { :hq_news_item => @hq_news_item, :branch_news_item => @branch_news_item }

否则,铁路会赢得真正的理解,你们通过什么是局部的变数,以及你作为使铁路发挥作用的理由而通过的东西。

问题回答

为什么你不使用成员变量@hq_news_item?

我认为,如果我在当地有变数,我就使用当地人的方法,那就把另一个人称作。

该法典在铁路操作2.3.8条。

<% f.fields_for :member_collection do |builder| %> 

  <%= render "membrer_collection_fields", :form => builder %> 

<% end %>

在此情况下,我有一部分——成员——收集——有当地变量的实地。





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