$check = array("this", "that", "to be", "not to be");
$yes = $no = array();
I m试图检查,是每个阵列项目check。 其中载有“be”。
如果在<代码>后添加“es,则在<代码>No上添加。
Seems 我必须使用一种定期表达方式,请你帮助我组成吗?
如果你想把<代码>be 而不是be作为附件,你可以使用:
$check = array("this", "that", "to be", "not to be");
$yes = $no = array();
foreach($check as $v) {
if(preg_match( /be/ ,$v)) {
$yes[] = $v;
} else {
$no[] = $v;
}
}
foreach($array as $arr)
{
if(in_array( be , explode( , $arr)) == true)
$yes[] = $arr;
else
$no[] = $arr;
}
参看in_array()。
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