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C++ 如何超越青春期的特性,将运输退回到一条线的开端似乎不可行
原标题:C++ how to overwrite a character in console, return carriage to start of line doesn t seem to work

我的问题是,我如何获得第10号——0号——在同一行文上打印,用WIN32或GNUC编辑,以简单的方式,如我以下的法典,相互重复书写:

This is what I have so far:

#include <iomanip>
#include <iostream>
using namespace std;

#ifdef __GNUC__
#include <unistd.h>
#elif defined _WIN32
#include <cstdlib>
#endif

int main()
{

  cout << "CTRL=C to exit...
";

  for (int units = 10; units > 0; units--)
  {
    cout << units <<  
 ;
    cout.flush();
#ifdef __GNUC__
    sleep(1); //one second
#elif defined _WIN32
    _sleep(1000); //one thousand milliseconds
#endif

    //cout << "
";// CR

  }

  return 0;
} //main

但这只是印刷品:

10 9 8 7 6 5 4 3 2 1

最佳回答

我确实做了一些微小的改动(主要是要清理,使之更加可读):

#include <iomanip>
#include <iostream>
using namespace std;

#ifdef __GNUC__
#include <unistd.h>
#define pause(n) sleep(n)
#elif defined _WIN32
#include <cstdlib>
#define pause(n) _sleep((n)*1000)
#endif

int main()
{

  cout << "CTRL=C to exit...
";

  for (int units = 10; units > -1; units--)
  {
    cout << setw(2) << setprecision(2) << units <<  
 ;
    cout.flush();
    pause(1);
  }
  return 0;
}

该公司与VC++和Cygwin公司进行了罚款。 如果它不从事ming工作,那么它就象一个执行问题一样,对我有好处。

问题回答

我建议你为此使用Ncurs或另一个图书馆,但这样做没有固定的方法。

您是否尝试过<条码>?





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