堕胎问题,但我可以指出:
for f in sorted(os.listdir( . )): print f
产出:
p1.html
p10.html
p11.html
p12.html
p13.html
p14.html
p15.html
p16.html
p17.html
p18.html
p19.html
p2.html
p20.html
p21.html
p22.html
p3.html
p4.html
...
显然,我想按编号分类,我可以与这一关键事项做些什么:f.split(......)[0][1:],但如何提及这一关键之处?
我尝试了,以分类(os.listdir ( ), 钥匙=f.split( )[0][1:],但当然没有工作。
TIA
你们需要一个lam语:
sorted(os.listdir( . ), key=lambda f: int(f.split( . )[0][1:]))
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