Question

I have a model and a modelform to change some settings. The form is displayed allright, with the correct values, but when I submit the form one field is missing in the request.POST dict.

模式:

class NodeSettings(models.Model):
    nodetype = models.CharField(max_length=8, editable=False)
    nodeserial = models.IntegerField(editable=False)
    upper_limit = models.FloatField(null=True, blank=True,
                                    help_text="Values above this limit will be of different color.")
    graph_time = models.IntegerField(null=True, blank=True,
                                     help_text="The `width  of the graph, in minutes.")
    tick_time = models.IntegerField(null=True, blank=True,
                                    help_text="Number of minutes between `ticks  in the graph.")
    graph_height = models.IntegerField(null=True, blank=True,
                                       help_text="The top value of the graphs Y-axis.")

    class Meta:
        unique_together = ("nodetype", "nodeserial")

观点类别(采用Django1.3的、有等级观点的Im):

class EditNodeView(TemplateView):
    template_name =  live/editnode.html 

    class NodeSettingsForm(forms.ModelForm):
        class Meta:
            model = NodeSettings

    # Some stuff cut out

    def post(self, request, *args, **kwargs):
        nodetype = request.POST[ nodetype ]
        nodeserial = request.POST[ nodeserial ]

        #  logger  is a Django logger instance defined in the settings
        logger.debug( nodetype   = %r  % nodetype)
        logger.debug( nodeserial = %r  % nodeserial)

        try:
            instance = NodeSettings.objects.get(nodetype=nodetype, nodeserial=nodeserial)
            logger.debug( have existing instance )
        except NodeSettings.DoesNotExist:
            instance = NodeSettings(nodetype=nodetype, nodeserial=nodeserial)
            logger.debug( creating new instance )

        logger.debug( instance.tick_time = %r  % instance.tick_time)

        try:
            logger.debug( POST[tick_time] = %r  % request.POST[ tick_time ])
        except Exception, e:
            logger.debug( error: %r  % e)

        form = EditNodeView.NodeSettingsForm(request.POST, instance=instance)
        if form.is_valid():
            from django.http import HttpResponse
            form.save()
            return HttpResponse()
        else:
            return super(EditNodeView, self).get(request, *args, **kwargs)

模板的相关部分:

<form action="{{ url }}edit_node/" method="POST">
  {% csrf_token %}
  <table>
    {{ form.as_table }}
  </table>
  <input type="submit" value="Ok" />
</form>

The debugproducts:

2011-04-12 16:18:05,972 DEBUG nodetype   = u V10 
2011-04-12 16:18:05,972 DEBUG nodeserial = u 4711 
2011-04-12 16:18:06,038 DEBUG have existing instance
2011-04-12 16:18:06,038 DEBUG instance.tick_time = 5
2011-04-12 16:18:06,039 DEBUG error: MultiValueDictKeyError("Key  tick_time  not found in <QueryDict: {u nodetype : [u V10 ], u graph_time : [u 5 ], u upper_limit : [u  ], u nodeserial : [u 4711 ], u csrfmiddlewaretoken : [u fb11c9660ed5f51bcf0fa39f71e01c92 ], u graph_height : [u 25 ]}>",)

如你所看到,实地标准——时间在请求书的空白处没有。 POST。

应当指出,这个领域属于网络浏览器,在研究超文本来源时,它仅以形式看待其他领域。

任何人在什么情况下会错?

Answer 1

由于你采用通用观点,因此最好将ProcessFormView 而不是Template 观点:



http://www.ohchr.org。

我用<代码>TemplateView对你的代码进行了试验:

class EditNodeView(TemplateView):

Do you have a get_context_data to push the form?

def get_context_data(self, **kwargs):
    instance = NodeSettings.objects.get(pk=kwargs[ node_id ])
    form = EditNodeView.NodeSettingsForm(instance=instance)
    context = super(EditNodeView, self).get_context_data(**kwargs)
    context[ form ] = form
    return context

The best way for editing existing objects is to get by primary key, I have the following in the urls.py:

url(r ^edit-node/(?P<node_id>d+)/$ , EditNodeView.as_view(), name= edit-node ),

I fetch the instance by primary key, might want to do some checking above like throwing 404 if not present.

In your models, you have nodetype and nodeserial as editable=False, how do you display or create those items if they are set to not editable? I ve set them to True for testing purposes.

在模板中,我把第一行改为:

<form action="" method="POST">

I m aware that there are a lot of changes but the above can view and edit your model properly. You could set the nodetype and nodeserial to be read-only at the form level to prevent people from editing it.

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