我有下一个问题:
x=[[ 1 , 7 , U1 ], [ 1.5 , 8 , U1 ]]
y=sum(sum(float(el) for el in els[:-1]) for els in x)
print(x)
print(y)
在这一法典中,所有数字的总和,但我想从第一[1、7、U1]、第一编号和第二[1.5、8、U1]、第一编号和第二[1.5、8、U1]和同一数字中总结。
最终结果如下:
y=
[ [2.5], #1+1.5=2.5
[15]] #7+8=15
>>> x=[[ 1 , 7 , U1 ], [ 1.5 , 8 , U1 ]]
>>> zip(*x)
[( 1 , 1.5 ), ( 7 , 8 ), ( U1 , U1 )]
>>> [[sum(float(n) for n in nums)] for nums in zip(*x)[:-1]]
[[2.5], [15.0]]
zip(*x) is a simple way to transpose the matrix (switch rows <--> columns), and this allows you to easily sum each row.
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