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原标题:Python sum trouble

我有下一个问题:

x=[[ 1 ,  7 ,  U1 ], [ 1.5 ,  8 ,  U1 ]]
y=sum(sum(float(el) for el in els[:-1]) for els in x) 

print(x)
print(y)

在这一法典中,所有数字的总和,但我想从第一[1、7、U1]、第一编号和第二[1.5、8、U1]、第一编号和第二[1.5、8、U1]和同一数字中总结。

最终结果如下:

y=
[ [2.5],                                #1+1.5=2.5
  [15]]                                 #7+8=15
最佳回答
>>> x=[[ 1 ,  7 ,  U1 ], [ 1.5 ,  8 ,  U1 ]]
>>> zip(*x)
[( 1 ,  1.5 ), ( 7 ,  8 ), ( U1 ,  U1 )]
>>> [[sum(float(n) for n in nums)] for nums in zip(*x)[:-1]]
[[2.5], [15.0]]

zip(*x) is a simple way to transpose the matrix (switch rows <--> columns), and this allows you to easily sum each row.

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