我可以使用单独档案这样做,但我如何把一线连接到档案的开始?
f=open( log.txt , a )
f.seek(0) #get to the first position
f.write("text")
f.close()
这从档案的结尾开始,因为档案以传译方式开启。
我可以使用单独档案这样做,但我如何把一线连接到档案的开始?
f=open( log.txt , a )
f.seek(0) #get to the first position
f.write("text")
f.close()
这从档案的结尾开始,因为档案以传译方式开启。
在<方式代码> a 或 a+
上,任何书面材料均在文档末尾,即便在目前<代码>write(<>>功能启动时,档案查询人不在档案的末尾:在任何书面材料之前,该查询人已移至卷宗的末尾。 你可以以两种方式做你们想要的东西。
1st way, 如无问题将档案装上记忆:
def line_prepender(filename, line):
with open(filename, r+ ) as f:
content = f.read()
f.seek(0, 0)
f.write(line.rstrip(
) +
+ content)
<>2nd way:
def line_pre_adder(filename, line_to_prepend):
f = fileinput.input(filename, inplace=1)
for xline in f:
if f.isfirstline():
print line_to_prepend.rstrip(
) +
+ xline,
else:
print xline,
我不知道这种方法如何在一生中发挥作用,能否在大档案中加以使用。 提交意见的第1论点是能够重写一条线的;为了开展地方行动,必须向前推进或后退,但我不知道这一机制。
在我所熟悉的所有档案系统中,你无法做到这一点。 你必须使用辅助档案(然后可以改名取原始档案的名称)。
为了向国家扫盲委员会提出答案,我认为最有效的办法是:
def insert(originalfile,string):
with open(originalfile, r ) as f:
with open( newfile.txt , w ) as f2:
f2.write(string)
f2.write(f.read())
os.remove(originalfile)
os.rename( newfile.txt ,originalfile)
不同的想法:
(1) 你将原始档案作为变量予以保存。
(2) 你用新信息推翻原始档案。
(3) 你在数据库中附上新资料。
法典:
with open(<filename>, r ) as contents:
save = contents.read()
with open(<filename>, w ) as contents:
contents.write(< New Information >)
with open(<filename>, a ) as contents:
contents.write(save)
如果你不想再次书写档案,那么这样做的明确方式如下:
with open("a.txt", r+ ) as fp:
lines = fp.readlines() # lines is list of line, each element ...
lines.insert(0, one_line) # you can use any index if you know the line index
fp.seek(0) # file pointer locates at the beginning to write the whole file again
fp.writelines(lines) # write whole lists again to the same file
请注意,这不是替代。 它再次撰写档案。
简言之,你读到一份档案,将其保存到一份清单中,并修改名单,再次将名单写到一份新档案中,并附上相同的档案。
num = [1, 2, 3] #List containing Integers
with open("ex3.txt", r+ ) as file:
readcontent = file.read() # store the read value of exe.txt into
# readcontent
file.seek(0, 0) #Takes the cursor to top line
for i in num: # writing content of list One by One.
file.write(str(i) + "
") #convert int to str since write() deals
# with str
file.write(readcontent) #after content of string are written, I return
#back content that were in the file
任何内在职能都无法做到这一点,因为这将非常低效率。 每次在前面添加一条线时,你必须改变档案的现有内容。
可在文档结尾处读出的“Unix/article tail
with open("fruits.txt", "r+") as file:
file.write("bab111y")
file.seek(0)
content = file.read()
print(content)
如果档案太大,无法作为清单使用,而且你只是想推翻档案,那么,你可以先以倒置的次序书写档案,然后在档案结束时读到一条线(并写到另一个档案),备案模块。
对现有解决办法的改进如下:
def prepend_text(filename: Union[str, Path], text: str):
with fileinput.input(filename, inplace=True) as file:
for line in file:
if file.isfirstline():
print(text)
print(line, end="")
它被打上了型号,更能读取,近年来使用一些改进标准,如环境主管:
我尝试了另一种做法:
I wrote first line into a header.csv
file. body.csv
was the second file. Used Windows type
command to concatenate them one by one into final.csv
.
import os
os.system( type c:\header.csv c:\ody.csv > c:\final.csv )
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