我正试图把一个字符串转换成字典。示例:
Milk, Cheese, Bottle
程序将把它转换成字典。
{"Milk":"NULL", "Cheese":"NULL", "Bottle":"NULL"}
我该怎么做?
我正试图把一个字符串转换成字典。示例:
Milk, Cheese, Bottle
程序将把它转换成字典。
{"Milk":"NULL", "Cheese":"NULL", "Bottle":"NULL"}
我该怎么做?
>>> string = Milk, Cheese, Bottle
>>> dict((key, None) for key in string.split( , ))
{ Cheese : None, Milk : None, Bottle : None}
>>> s = "Milk, Cheese, Bottle"
>>> d = dict.fromkeys(s.split( , ),"NULL")
>>> d
{ Cheese : NULL , Milk : NULL , Bottle : NULL }
dict.fromkeys((k.strip() for k in "Milk, Cheese, Bottle".split( , )), NULL )
s = Milk, Cheese
d = { }
for s in s.split( , ):
d[s] = NULL
您还可以在最新的Python版本中使用字典理解:
s = Milk, Cheese
d = {key: NULL for key in s.split( , )}
>>> from collections import defaultdict:
>>> s = "Milk, Cheese, Bottle"
>>> j = s.split( , )
>>> d = defaultdict()
>>> for k in j:
d[k]= NULL
>>> dict(d)
这基本上与Zaur-Nasibov的解决方案相同,但使用列表理解在较少的行中运行for循环
s = "Milk, Cheese, Bottle"
d = dict((i, None) for i in [i.strip() for i in s.split( , )])
>>> print d
{ Cheese : None, Milk : None, Bottle : None}
希望这能有所帮助
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