Question

核对以下编码

def wipe_mutterings_from( sentence )
   while sentence.include?  ( 
     open = sentence.index(  (  )
     close = sentence.index(  ) , open )
     sentence[open..close] =    if close
   end
end

foo= abbba (jjjj) kkkkkk 
wipe_mutterings_from( foo )
p foo

In my understanding I have passed the string by ref to the function (much like is done in lower level languages like c/cpp).
Is it possible to pass the string only by value (like in PHP)?
I am fully aware I can duplicate the string inside the function and work only on the copy.

Answer 1

简言之,一切都以提及方式在鲁比通过,扼杀是 mu。通常要做的是<代码>dup。如你所提到,这是这种方法中的第一个。

然而,一个更为容易的方法是,仅仅不做<条码>[开放],而是像<条码>[0......开放]+句[(包括+1.-1]

Answer 2

或者,你可以尝试更“人工”的方式(在休息和指数计算时消除):

foo =  abbba (jjjj) kkkkkk 
p foo.sub(/(.*) /,   )

Answer 3

您可以试图仅寄送一份这一说明的副本。

foo= abbba (jjjj) kkkkkk 
wipe_mutterings_from( foo.clone )
p foo

Answer 4

我看不出你为什么会给这一职能造成新的扼杀,并回去。它读得好得多,而且不太奇怪:

foo= abbba (jjjj) kkkkkk 
new_foo = wipe_mutterings_from( foo )
p new_foo

甚至

foo= abbba (jjjj) kkkkkk 
foo = wipe_mutterings_from( foo )
p foo

但我更喜欢后者。

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