在C++中,为什么在我以价值通过时,把固定的复印件拖到另一个固定的状态?
原文：In C++, why doesn t the copy of a constant also have to be a constant when I pass it by value?
原文：In C++, why doesn t the copy of a constant also have to be a constant when I pass it by value?
例如,这部法律汇编(g++ 13.1.0),使我的产出“数字为20”。