Question

I have a list of strings of the following pattern: "namemiddleName". What is the nicest way to turn into a list in which all the elements are just "name"? (i.e split the string and leave only the "name" part)

Thanks, Li

Answer 1

List<string> originalList = ...
List<string> newList = originalList.Select(s => s.Split( \ )[0]).ToList()

Answer 2

List<string> original = ...
List<string> nameOnly = original.ConvertAll(s => s.Substring(0, s.IndexOf( \ )));

如果原始列表的某些元素中可能没有字符，则需要进行额外检查以避免出现异常：

List<string> nameOnly = original.ConvertAll(s => {
                                                     int i = s.IndexOf( \ );
                                                     return (i == -1) 
                                                         ? s
                                                         : s.Substring(0, i);
                                                 });

Answer 3

//your list of strings in format (namemiddleName)
List<string> list;
List<string> newList;

foreach(string item in list)
   newList.Add(item.Substring(0, item.IndexOf("\")));

这将使你的字符串列表的副本变成一个新的，格式像你想要的。

Answer 4

Tokenize "/" and assign the first string to name variable. Or just make loop of all those strings in a list and inside a loop do a loop on a string length which puts chars into variable and exits when reaches "/" and then stores it as a name.

Answer 5

这里有一个不创建新列表的正则表达式解决方案。

for(int i = 0; i < list.count; i++)
{
     list[i] = Regex.Match(List[i],@"^w+").value      
}

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