因此,我在使用Android SDK时相当笨拙(与纯java相比,我觉得它非常令人困惑)。这是我使用它的第二天,全程自学。
说到这里,我想知道如何让Rect充当按钮。
基本上,用户会点击某个矩形(已经在屏幕上绘制,但如何绘制它是另一个问题;我完全迷上了Canvas),然后我想检查他们触摸的x/y坐标,看看它是否包含在矩形内,这时应用程序会做一些事情(比如在UI上的某个文本视图中更改文本)。
我已经尝试了大约一个小时,但没有成功,如果有人能写一小段关于如何做到这一点的源代码,我将不胜感激!
因此,我在使用Android SDK时相当笨拙(与纯java相比,我觉得它非常令人困惑)。这是我使用它的第二天,全程自学。
说到这里,我想知道如何让Rect充当按钮。
基本上,用户会点击某个矩形(已经在屏幕上绘制,但如何绘制它是另一个问题;我完全迷上了Canvas),然后我想检查他们触摸的x/y坐标,看看它是否包含在矩形内,这时应用程序会做一些事情(比如在UI上的某个文本视图中更改文本)。
我已经尝试了大约一个小时,但没有成功,如果有人能写一小段关于如何做到这一点的源代码,我将不胜感激!
所以我假设你使用的是SurfaceView。你想要的应该很简单。
首先,覆盖曲面视图中的触摸事件,并存储上次触摸的坐标:
@Override
public void onTouchEvent(MotionEvent event) {
x = event.getX();
y = event.getY();
}
然后,检查rect是否包含该坐标:
Rect rect = new Rect() // Your rect
if (rect.contains(x, y) {
// Contained in your rect
} else {
// Not contained in your rect
}
我相信这就是你的要求?如果你还感到困惑,请告诉我。
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