In the below sample, the last 2 lines in the B.Go() method both call the Go() method from class A. Are they functionally identical? Is the only benefit to using super() that I don t have to know the inherited class name?
class A(object):
def Go(self):
print "Calling A.Go()"
class B(A):
def Go(self):
super(B, self).Go()
A.Go(self)
inst = B()
inst.Go()
<super(>> 直接打电话到A.Gocan tsuper(B, Self.Go() 查询方法解决令中的下一个方法。 它称之为“<>m>本应被称作的>代码>B但根本不适用该方法。 在直线继承中,这总是<代码>A,因此不存在实际差异(除你重复的那类)。 然而,在多重继承情况下,正常方法解决令中的下一个类别不一定是目前类别的直接基流。 见关于钻石继承的解释,。 Guido s original interpret of theseities.
并非确切。 只使用表面的B,就有一个例子。 第2行是A类的新例子,可能对初始使用人产生副作用,并且不分享其他案例属性或状态(B例inst)。
它们完全不同。 将A(a)Go(a)(a)引出一个全新的物体,但与制造该物体的原样并不相同。
你的榜样过于简单,你需要一个表明真正不同行为的国家。
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