Use int.TryParse():

string input = "141241";
int ouput;
bool result = int.TryParse(input, out output);

具体结果如下:true。

你们可以使用以下法典:

    string numbers = "numbers you want to check";

    Regex regex = new Regex("^[0-9]+$"));

    if (regex.IsMatch(numbers))
    {
        //string value is a number
    }

public static void Main()
        {
            string id = "141241";
            string id1 = "232a23";
            string id2 = "12412a";

            validation( id,  id1,  id2);
        }

       public static void validation(params object[] list)
        {
            string s = "";
            int result;
            string _Msg = "";

            for (int i = 0; i < list.Length; i++)
            {
                s = (list[i].ToString());

               if (string.IsNullOrEmpty(s))
               {
                   _Msg = "Please Enter the value"; 
               }

               if (int.TryParse(s, out result))
               {
                   _Msg = "Enter  " + s.ToString() + ", value is Integer";

               }
               else
               {
                   _Msg = "This is not Integer value ";
               }
            }
        }

Try This

here i perform addition of no and concatenation of string

 private void button1_Click(object sender, EventArgs e)
        {
            bool chk,chk1;
            int chkq;
            chk = int.TryParse(textBox1.Text, out chkq);
            chk1 = int.TryParse(textBox2.Text, out chkq);
            if (chk1 && chk)
            {
                double a = Convert.ToDouble(textBox1.Text);
                double b = Convert.ToDouble(textBox2.Text);
                double c = a + b;
                textBox3.Text = Convert.ToString(c);
            }
            else
            {
                string f, d,s;
                f = textBox1.Text;
                d = textBox2.Text;
                s = f + d;
                textBox3.Text = s;
            }
        }

我不是特别高技能的策划者,但当我需要解决这一问题时,我选择了可能非常不合法的解决方法,但符合我的需求。

    private bool IsValidNumber(string _checkString, string _checkType)
    {
        float _checkF;
        int _checkI;
        bool _result = false;

        switch (_checkType)
        {
            case "int":
                _result = int.TryParse(_checkString, out _checkI);
                break;
            case "float":
                _result = Single.TryParse(_checkString, out _checkF);
                break;
        }
        return _result;

    }

I simply call this with something like:

if (IsValidNumber("1.2", "float")) etc...

It means that I can get a simple true/false answer back during If... Then comparisons, and that was the important factor for me. If I need to check for other types, then I add a variable, and a case statement as required.

use this

 double num;
    string candidate = "1";
    if (double.TryParse(candidate, out num))
    {
        // It s a number!


 }

int num;
bool isNumeric = int.TryParse("123", out num);

namespace Exception
{
    class Program
    {
        static void Main(string[] args)
        {
            bool isNumeric;
            int n;
            do
            {
                Console.Write("Enter a number:");
                isNumeric = int.TryParse(Console.ReadLine(), out n);
            } while (isNumeric == false);
            Console.WriteLine("Thanks for entering number" + n);
            Console.Read();
        }
    }
}

Regex.IsMatch(stringToBeChecked, @"^d+$")

Regex.IsMatch("141241", @"^d+$")  // True

Regex.IsMatch("232a23", @"^d+$")  // False

Regex.IsMatch("12412a", @"^d+$")  // False

一些建议的解决办法是,这些解决办法没有考虑到各种不同的紧急编号格式。 以下职能:

public bool IsNumber(String value)
{
    double d;
    if (string.IsNullOrWhiteSpace(value)) 
        return false; 
    else        
        return double.TryParse(value.Trim(), System.Globalization.NumberStyles.Any,
                            System.Globalization.CultureInfo.InvariantCulture, out d);
}

缔约国认为,各种浮动编号风格,如 de(英文)和decima comma(德国)都是允许的。 如果情况并非如此,则改变序号。 注:Any <>/code> > >不包括中程,因为双倍不支持。