目前,我有一套要点。 我正试图给各点人中的一个要素带来价值,但我却有分歧。
aStruct->anArray[0]->string = test;
aStruct contains a char** anArray and char *string. char *test = "test".
当我试图做我所做的事情时,我会遇到分裂问题。 这种指挥是否无效?
struct aStruct
{
char **anArray;
};
我使用电话使面积达到10。
目前,我有一套要点。 我正试图给各点人中的一个要素带来价值,但我却有分歧。
aStruct->anArray[0]->string = test;
aStruct contains a char** anArray and char *string. char *test = "test".
当我试图做我所做的事情时,我会遇到分裂问题。 这种指挥是否无效?
struct aStruct
{
char **anArray;
};
我使用电话使面积达到10。
aStruct->anArray[0]->string = test;
aStruct contains a char** anArray and char *string. char *test = "test".
这种指挥是否无效?
当然,aStruct->anArray[0]
将改为char*
,tn t有成员->string
。
除此以外,如果你真的汇编,而且你只贴上错误的代码,那么如果适当分配<代码>an Array<<>>>>>/code>,且其规模是正确的,你就没有被分割。 因此,在您的方案中,你需要这样的内容:
aStruct->anArray = malloc(size * sizeof(*aStruct->anArray));
你们的面积至少是一例,但一般而言,你们需要接触的内容数目。
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