也许可以使用单一管理标准,但很难向用户提供它们所依据的规则。 更传统的做法,使你们得到反馈意见,即你在《倡议》中可以用来告诉用户,哪些规则没有得到遵守:

function checkPwd(str) {
    if (str.length < 6) {
        return("too_short");
    } else if (str.length > 50) {
        return("too_long");
    } else if (str.search(/d/) == -1) {
        return("no_num");
    } else if (str.search(/[a-zA-Z]/) == -1) {
        return("no_letter");
    } else if (str.search(/[^a-zA-Z0-9!@#$\%^&*()\_+]/) != -1) {
        return("bad_char");
    }
    return("ok");
}

在 j子回答之后,我写了这一dle子,以测试他的解决方案,稍作改动,使之更能直观:

http://jsfiddle.net/9RB49/1/

checkPwd = function() {
    var str = document.getElementById( pass ).value;
    if (str.length < 6) {
        alert("too_short");
        return("too_short");
    } else if (str.length > 50) {
        alert("too_long");
        return("too_long");
    } else if (str.search(/d/) == -1) {
        alert("no_num");
        return("no_num");
    } else if (str.search(/[a-zA-Z]/) == -1) {
        alert("no_letter");
        return("no_letter");
    } else if (str.search(/[^a-zA-Z0-9!@#$\%^&*()\_+.,;:]/) != -1) {
        alert("bad_char");
        return("bad_char");
    }
    alert("oukey!!");
    return("ok");
}

A more elegant and self-contained regex to match these (common) password requirements is:

^(?=.*[A-Za-z])(?=.*\d)[A-Za-z\d^a-zA-Z0-9].{5,50}$

The elegant touch here is that you don t have to hard-code symbols such as $ @ # etc.

为了接受所有符号,你只是说:“也接受所有非字母数字特性,而不是数字”。

Min and Max number of characters requirement

The final part of the regex {5,50} is the min and max number of characters, if the password is less than 6 or more than 50 characters entered the regex returns a non match.

我有一席之地,但只是一.。

^(?:(?<Numbers>[0-9]{1})|(?<Alpha>[a-zA-Z]{1})|(?<Special>[^a-zA-Z0-9]{1})){6,50}$

让我解释一下,以及如何检查经过测试的密码是否正确:

There are three named groups in the regex. 1) "Numbers": will match a single number in the string. 2) "Alpha": will match a single character from "a" to "z" or "A" to "Z" 3) "Special": will match a single character not being "Alpha" or "Numbers"

这三个名称的群体被归入另一个类别,{6,50}<>>>>>>建议 regex用机器捕获至少6个上述群体,但不超过50个。

为确保进入正确的密码,你必须检查是否配对,然后,如果相应群体被捕获达到你所期望的程度。 I m a C# developer and una t knowledge, how it work in javascript, but in C#, Yousss toeck:

match.Groups["Numbers"].Captures.Count > 1

希望它能以 j语开展工作! 亲爱!

我使用了这一方法。

export const validatePassword = password => {
  const re = /^(?=.*[A-Za-z])(?=.*d)[a-zA-Z0-9!@#$%^&*()~¥=_+}{":; ?/>.<,`-|[]]{6,50}$/
  return re.test(password)
}

International UTF-8

这里的任何解决办法都不允许国际信件,即:EöÖæÆóÓúÚáÁ,但主要侧重于english alphabet。

The following regEx use unicode, UTF-8, togni Superior and low case and, so, Admission international nature:

// Match uppercase, lowercase, digit or #$!%*?& and make sure the length is 6 to 50 in length  
const pwdFilter = /^(?=.*p{Ll})(?=.*p{Lu})(?=.*[d|@#$!%*?&])[p{L}d@#$!%*?&]{6,50}$/gmu

if (!pwdFilter.test(pwd)) {
    // Show error that password has to be adjusted to match criteria
}

This regEx

/^(?=*p{Ll})(?=*p{Lu})(?)=*[>[>#$%!*&] [p{L}d@#$!%*?&]{6,50}$/gmu

checks if an uppercase, lowercase, digit or #$!%*?& are used in the password. It also limits the length to be 6 minimum and maximum 50 (note that the length of ??????‍? emojis counts as more than one character in the length). The u in the end, tells it to use UTF-8.

DEMO https://jsfiddle.net/ssuryar/bjuhkt09/

<form>
<input type="text" name="testpwd" id="testpwd" class="form=control" onkeyup="checksPassword(this.value)"/>
<input type="submit" value="Submit" /><br />
<span class="error_message spassword_error" style="display: none;">Enter minimum 8 chars with atleast 1 number, lower, upper &amp; special(@#$%&!-_&amp;) char.</span>
</form>

function checksPassword(password){
var pattern = /^.*(?=.{8,20})(?=.*d)(?=.*[a-z])(?=.*[A-Z])(?=.*[@#$%&!-_]).*$/;
if(!pattern.test(password)) {
$(".spassword_error").show();
}else
{
$(".spassword_error").hide();
}
}