Question

是否迅速将数字转换成倍数(图例:“0.5e10”或“-5e20”)以减小或翻一番?

Update: I found Parse a Number from Exponential Notation but the examples won t work for me unless I specified a culture.

解决办法:

double test = double.Parse("1.50E-15", CultureInfo.InvariantCulture);

Answer 1

如果您的文化使用<条码>,作为精度分离器,则只有<条码> 两倍。

如果您的文化使用其他东西(例如,>),或希望确保您的申请在每台电脑上都发挥作用,则您应使用编码>。

double.Parse("1.50E-15", CultureInfo.InvariantCulture)

Answer 2

标准 ,double.Parse 或

实例:

// AllowExponent is implicit
var number1 = double.Parse("0.5e10");
Debug.Assert(number1 == 5000000000.0);

// AllowExponent must be given explicitly
var number2 = decimal.Parse("0.5e10", NumberStyles.AllowExponent);
Debug.Assert(number2 == 5000000000m);

另外,见MSDN条款 Parsing Numeric Strings<>。只要<代码>NumberStyles.AllowExponent选项在上指明 Parse方法(即double>的缺省法),规定这种扼杀将处以罚款。

NB: As the questioner points out, the exponential notation of "e10" for example does not work in all cultures. Specifying en-US culture however ensures that it works. I suspect CultureInfo.InvariantCulture should also do the trick.

Answer 3

@Noldorin正在正确尝试这一法典:

string str = "-5e20";
double d = double.Parse(str);
Console.WriteLine(str);

Answer 4

Math.Round 它将重新编号,以便删除。

Math.Round(Double.Parse("3,55E-15"),2)

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