Question

能否在下午写出一项功能,该功能提出论据,并印刷“h+a”的产物,而“h”是当地变量。之后,它就应该返回自己,只增加一个。

Answer 1

是的,你可以

def f(a):
    def inner(h, a):
        print h+a
        return lambda (x): inner(h+1, x)
    return inner(1, a)

实例

g = f(0) # +1
g = g(0) # +2
g = g(0) # +3

f(0) # +1
g(0) # +4
g(0) # +4

印刷

Q.E.D.

Answer 2

在3年级,你可以这样做:

>>> def f(a):
...     h = 1
...     def inner():
...             nonlocal h
...             print(a+h)
...             h += 1
...             return inner
...     return inner
... 
>>> g = f(3)  
>>> g = g()
4
>>> g = g()
5 
>>> g = g()
6
>>> g()()()
7 
8
9
<function inner at 0xb71bcd6c>

以前的版本要求放弃:

>>> def f(a):
...     h = [1]
...     def inner():
...             print a + h[0]
...             h[0] += 1
...             return inner
...     return inner
... 
>>> f(3)()()()
4  
5
6
<function inner at 0x10041f050>
>>>

(ETA:我猜测我误解了问题的一部分,因为你似乎希望通过t>f(以及这种回归本身)来恢复职能,以提出论点,但这种改动是微不足道的。)

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