我的问题是:
我怎么能找到数字下降的gram本指数?
在马特拉布,解决办法是容易的。 HISTC从事以下工作:
[counts,bin] = histc(data,edges)
"bin" being what I am looking for.
但是,我是在R,而R并没有提议职能性的<代码>hist功能。 我认为,我可以采用一些法典行文(将一些东西用在<条码>>>、<条码>和<条码>和>;),但鉴于我需要做很多工作,我想找到一个更加棘手的解决办法。
自2006年以来 在R,我没有经历过,我希望能够找到一个trick的解决办法,以另一种方式解决这一问题。
The hist function will return the breakpoints between the bins if you do not already have them. You can then use the findInterval function to find which interval/bin each of your points falls into:
> tmp <- hist(iris$Petal.Width)
> findInterval(iris$Petal.Width, tmp$breaks)
[1] 2 2 2 2 2 3 2 2 2 1 2 2 1 1 2 3 3 2 2 2 2 3 2 3 2
[26] 2 3 2 2 2 2 3 1 2 2 2 2 1 2 2 2 2 2 4 3 2 2 2 2 2
[51] 7 8 8 7 8 7 9 6 7 7 6 8 6 7 7 7 8 6 8 6 10 7 8 7 7
[76] 7 7 9 8 6 6 6 7 9 8 9 8 7 7 7 7 7 7 6 7 7 7 7 6 7
[101] 13 10 11 10 12 11 9 10 10 13 11 10 11 11 13 12 10 12 12 8 12 11 11 10 11
[126] 10 10 10 11 9 10 11 12 8 7 12 13 10 10 11 13 12 10 12 13 12 10 11 12 10
> tmp2 <- .Last.value
> cbind( value=iris$Petal.Width, lower=tmp$breaks[tmp2], upper=tmp$breaks[tmp2+1])
value lower upper
[1,] 0.2 0.2 0.4
[2,] 0.2 0.2 0.4
[3,] 0.2 0.2 0.4
[4,] 0.2 0.2 0.4
[5,] 0.2 0.2 0.4
[6,] 0.4 0.4 0.6
[7,] 0.3 0.2 0.4
[8,] 0.2 0.2 0.4
[9,] 0.2 0.2 0.4
[10,] 0.1 0.0 0.2
为方便港务编码,有若干套R套(re)实施<编码>histc。 例如,
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