Question

The following Regex do?

    d{1,3}.?d{0,3}s[0-9a-zA-Z. -]{4,40}

我的理解是,数字是多少,但做了1,3次。

如果有人能够进一步解释,将不胜感激。

Answer 1

{n,m} is a finntifier, which means “atless n time, at most m time”。与所有qu抗体一样,它因违约而处于贪 gr状态,而支持它们的reg和 possess({n,m}?和{n,m}+。 ——不幸的是,网络支持前者,但不支持后者。

如未具体指明<代码>n,则该编码为0;如未具体说明<代码>m,则该编码为定数。

也就是说,你可以“重写”传统的<代码>*,+和?。

* is {0,};
+ is {1,};
? is {0,1}.

(note: I think the . in .? was meant to be a literal dot, which means it should be escaped, that is .?; the dot in a regex means "any character", except in a character class.)

条例本身:

d{1,3}        # match a digit, one to three times, followed by
.?             # any character, 0 or one time (see my remark), followed by
d{0,3}        # a digit, zero to three times, followed by
s             # a space character, followed by
[0-9a-zA-Z. -] # a digit, or any letter, or a dot, or a space, or a hyphen,
{4,40}         # 4 to 40 times

最后,应当指出,d in .NET Language is not limit un to 0-9, 它可以与统法协会的其他编码数字相匹配。

编辑:考虑到@AlanMoore的评述,固定的监管机构将:

d{1,3}(.d{1,3})?s[0-9a-zA-Z. -]{4,40}

Maybe this regex should be anchored, too... But this is a guess only.

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