Question

#include <stdio.h>

int main()
{
    printf("10110210310410512");
    return 0;
}

In gcc compiler when I execute this code it prints ABCDE. If I call printf with a string like printf("101110210310410512") it prints A1BCDE. Why does it behave like this?

Answer 1

Certain characters can be represented in character and string constants by escape sequences like (newline); these sequences look like two characters, but represent only one. In addition, an arbitrary byte-sized bit pattern can be specified by ooo where ooo is one to three octal digits (0...7) or by xhh where hh is one or more hexadecimal digits (0...9, a...f, A...F).

- K&R 《方案拟订语言》第2.3章

特别注意“one to three octal 位数”一语

Answer 2

<代码>101 产生于101 octal = 41 hex = 65 decimal。您的终端显示,由于它期望UTF-8或其他一些ASCII-衍生工具编码编码,因此按字母顺序显示为A。

八月份的越狱顺序可以长到三位数,因此额外编码<1><>1>仅为<1>>>>。

Answer 3

根据我的研究结果,我发现,他们重新命名了职业越狱顺序,在“<>条码/代码”之后,每3位数都算为职业编号。阁下:

101 in octal is equal to 65 in decimal , which in ASCII Code is A.

Similarly, 102 represents 66 in decimal, which in ASCII is B

103 represents 67 in decimal, which in ASCII is C and so on...

但是,就<代码>1011而言,它印刷了<代码>A1。因为只有头3位数被转换成正文,即:101/code>有效,但此后并非1。 http://code>101为A, 1仅为1。

希望有助于你们。 Dunno,为什么你使用这些途径?

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