Question

我用一个旁观灯块,我要点击每个物品和营地;照亮。每个项目都有一个类别,因此我认为休息会奏效,但我无法选择这些项目。

传真结构:

<div class="accordionContainer">
    <div class="accordion">
      <h3>Click This</h3>
      <div class="accordionContent" style="display:none">
      </div>
    <div>
    <div class="accordion">
      <h3>Click This</h3>
      <div class="accordionContent" style="display:none">
      </div>
    <div>
</div>

粉碎

detailsAccordion = browser.find_elements_by_class_name( accordion )
index = 1
for option in detailsAccordion:
    option.click()
    try:
        element = ui.WebDriverWait(ff, 10).until(lambda driver : driver.find_element_by_xpath("//div[@class= accordion ][" + str(index) + "]/div[@class= accordionContent ]").text != "" )
    except:
        print "Can t do it"
        browser.quit()
    index = index + 1
    n = nextNumber(n)
    browser.save_screenshot( {0}{1}.png .format(imagesPath, n))
    option.click()

这造成了以下错误。我审视了这一错误和现象;人们在互联网选择/环境方面遇到麻烦——我没有代理,无法肯定为什么开始这样做;

 [exec] Can t do it
 [exec] Traceback (most recent call last):
 [exec]   File "viewEmployeeUseCase.py", line 82, in <module>
 [exec]     ff.save_screenshot( {0}{1}.png .format(imagesPath, n))
 [exec]   File "C:Python26libsite-packagesselenium-2.20.0-py2.6.eggseleniumwebdriverfirefoxwebdriver.py", line 75, in save_screenshot
 [exec]     png = RemoteWebDriver.execute(self, Command.SCREENSHOT)[ value ]

 [exec]   File "C:Python26libsite-packagesselenium-2.20.0-py2.6.eggseleniumwebdriver
emotewebdriver.py", line 151, in execute
 [exec]     response = self.command_executor.execute(driver_command, params)

 [exec]   File "C:Python26libsite-packagesselenium-2.20.0-py2.6.eggseleniumwebdriver
emote
emote_connection.py", line 280, in execute
 [exec]     return self._request(url, method=command_info[0], data=data)
 [exec]   File "C:Python26libsite-packagesselenium-2.20.0-py2.6.eggseleniumwebdriver
emote
emote_connection.py", line 321, in _request
 [exec]     response = opener.open(request)
 [exec]   File "C:Python26liburllib2.py", line 391, in open
 [exec]     response = self._open(req, data)
 [exec]   File "C:Python26liburllib2.py", line 409, in _open
 [exec]      _open , req)
 [exec]   File "C:Python26liburllib2.py", line 369, in _call_chain
 [exec]     result = func(*args)
 [exec]   File "C:Python26liburllib2.py", line 1170, in http_open
 [exec]     return self.do_open(httplib.HTTPConnection, req)
 [exec]   File "C:Python26liburllib2.py", line 1145, in do_open
 [exec]     raise URLError(err)
 [exec] urllib2.URLError: <urlopen error [Errno 10061] No connection could be made because the target machine actively refused it>

• 做简单的事情;不等待内容去做工件的罚款和整件;我都想到的是:

for option in detailsAccordion:
    #print option
    option.click()
    WebDriverWait(ff, 2)
    n = nextNumber(n)
    ff.save_screenshot( {0}{1}.png .format(imagesPath, n))
    option.click()

Answer 1

我认为,不言而喻的等待是你想要的,我不认为你正在做任何事情。 “默示的等待是告诉网络司机在试图找到一个要素或要素时,如果无法立即获得这些要素或要素,就将占用一定时间。违约情况为0。一经确定,网络司机物体的寿命即为默示等待。 - http://seleniumhq.org/docs/04_webdriver_advanced.html#implicit-waits”rel=“nofollow”>Webdriver

你们真正想要的是 , 等待协议内容到场,然后接受屏幕。

Sorry, not a Python programmer, so I am guessing at the exact code. But I think you want something like:

detailsAccordion = browser.find_elements_by_class_name( accordion )
for option in detailsAccordion:
    option.click() # open div
    #Wait until the accordionContent div has text
    try:
        element = WebDriverWait(browser, 10).until(lambda option : option.find_element_by_class_name("accordionContent").text != "" )
    finally:
        #Throw error cause the div didn t populate
        browser.quit
    n = nextNumber(n)
    browser.save_screenshot( {0}{1}.png .format(imagesPath, n))
    option.click() #close div

UPDATE: Sorry, I think there are two major issues with the solution I originally suggested. (1) It should be except: instead of finally: since finally: always executes rather than just if there s a timeout error. (2) Unlike Watir-Webdriver, it seems that Selenium-Webdriver does not allow checking the accordionContent with respect to the current accordion element. The originally proposed solution is always checking the first accordionContent on the page (bad). The only way I could find the element with respect to another element is using xpath (or css-selector).

更新了以下两个概念:

detailsAccordion = browser.find_elements_by_class_name( accordion )
index = 1
for option in detailsAccordion:
    print option
    option.click()
    try:
        element = ui.WebDriverWait(browser, 10).until(lambda driver : driver.find_element_by_xpath("//div[@class= accordion ][" + str(index) + "]/div[@class= accordionContent ]").text != "" )
    except:
        # Error if div didn t populate
        print "Can t do it"
        browser.quit()
    index = index + 1
    n = nextNumber(n)
    browser.save_screenshot( {0}{1}.png .format(imagesPath, n))
    option.click()

友情链接