Question

Define a function SWAP(SCORES) to swap all those values in the list of SCORES, which are alternate elements. For example: If the SCORES contain [200, 456, 300, 100, 234, 678], the output should be displayed as [300, 200, 100, 456, 678, 234].

现在的安排模式是特殊的,因为如果[1,2,3,4,5,6]是命令,那么结果就是命令[3,1,4,2,6,5]。

while True:
    l=eval(input( List:  ))
    x=len(l)
    n=x//4
    t=4*n
    l1=l[:t]
    print(l1)
    l2=l[t:]
    print(l2)
    for i in range((len(l1)//2)):
        l1[i],l1[i+2]=l1[i+2],l1[i]
        #l1 shuffling over
    if len(l2)==1:
        l1+=l2
        print( Shuffled list: ,l1)
    elif len(l2)>=2:
        l2=l2[::-1]
        l1+=l2
        print( Shuffled list: ,l1)
    elif len(l2)==0:
        print( Shuffled list: ,l1)
        #treating l2 separately

这是我所尝试的,对我来说,这确实是行之有效的。

================================== RESTART: C:/Users/Harikrishnan/OneDrive/Desktop/peculiar shuffling q.py ==================================
List: [200,456,300,100,234,678]
[200, 456, 300, 100]
[234, 678]
Shuffled list: [300, 100, 200, 456, 678, 234]
List: [1,2,3,4]
[1, 2, 3, 4]
[]
Shuffled list: [3, 4, 1, 2]
List: [1,2,3,4,5]
[1, 2, 3, 4]
[5]
Shuffled list: [3, 4, 1, 2, 5]
List: [1,2,3,4,5,6,7]
[1, 2, 3, 4]
[5, 6, 7]
Shuffled list: [3, 4, 1, 2, 7, 6, 5]
List: [1,2,3,4,5,6,7,8]
[1, 2, 3, 4, 5, 6, 7, 8]
[]
Shuffled list: [3, 4, 5, 6, 1, 2, 7, 8]
List: 
Traceback (most recent call last):
  File "C:/Users/Harikrishnan/OneDrive/Desktop/peculiar shuffling q.py", line 2, in <module>
    l=eval(input( List:  ))
KeyboardInterrupt

我的逻辑是:直到第4点,所有东西都是罚款的。 Od的立场论点是 s弄的,甚至立场论点是 s弄的,在四起案件发生后:

Nothing was left after the 4n elements.
1 element was left,
2 elements were left,
3 elements were left.

我的朋友有另一个逻辑:

i 认为这一模式是最后两个因素,最后三个是第5号,最后四个是第6号,最后七个是第10号,最后八个是第11号是第12号

现在我感到困惑。我们谁是正确的?

Answer 1

#It is known that [200,456,300,100,234,678]
#has to be swapped to [300,200,100,456,234,678]
def swap(l):
    for i in range(2):
        while True:
            l[i],l[i+2]=l[i+2],l[i]
            i+=4
            if i>len(l)-3:
                break
while True:
    try:
        l=eval(input( Enter list:  ))
        swap(l)
        print(l)
    except KeyboardInterrupt:
        print( Testing done )
        break

Answer 2

def swap(lst):
    l=len(lst)
    l2=list(lst)
    l3=[]
    if l<4:
        for i in range(len(l2)):
            if i+2<len(l2):
                l3.append(l2[i+2])
                l3.append(l2[i])
    elif l>4:
        l4=lst[:4]
        l5=lst[4:]
        for i in range(len(l4)):
            if i+2<len(l4):
                l3.append(l4[i+2])
                l3.append(l4[i])
        for i in range(0,len(l5)-1,2):
            l5[i],l5[i+1]=l5[i+1],l5[i]
    lst=l3+l6
    return lst
print(swap([200,456,300,100,234,678]))
print(swap([200,456,300,100,234,678,9,10,67,69]))

Output: [300, 200, 100, 456, 678, 234] [300, 200, 100, 456, 678, 234, 10, 9, 69, 67]

所提到的问题不是普通的sh/tern。

看看理解的形象:1

Here is my thought process: For the first four elements, last two elements replace [n-2]th element for the next consecutive terms, each term is swapped with next one continously PS: All the best for exams broo!

Answer 3

But I think your code only swaps 1st with the third and 2nd with the fourth And I get the output as [300,100,200,456,234,678] I can try refining my code..

友情链接