Question

我想创建一个服务器, 以作为一堆杂货箱应用程序的容器。我做了一个杂货箱应用程序的服务器, 但我不明白如何修改 Web. xml 以适应许多应用程序。下面是 Web. xml 的单个杂货箱 : ( 从“ 恢复行动 MEAP ” 中几乎逐字读取 ) :

<?xml version="1.0" encoding="UTF-8"?>
...
<display-name>Servlet engine as a container of Restlet applications</display-name>
<servlet>
<servlet-name>CompanyServerApplication</servlet-name>
<servlet-class>org.restlet.ext.servlet.ServerServlet</servlet-class>
<init-param>
  <param-name>org.restlet.application</param-name>
  <param-value>server.CompanyServerApplication</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>CompanyServerApplication</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
</web-app>

Answer 1

简单地在您的 web.xml 中添加额外的和块。例如,我得到了单独的 restlet 应用程序, 用于用户请求和管理员请求。我的 Web.xml 看起来像这个:

<!-- user servlet -->
<servlet>
  <servlet-name>user</servlet-name>
  <servlet-class>org.restlet.ext.servlet.ServerServlet</servlet-class>
  <init-param>
    <param-name>org.restlet.application</param-name>
    <param-value>com.myapp.server.resource.user.UserApplication</param-value>
  </init-param>
  <init-param>
    <param-name>org.restlet.clients</param-name>
    <param-value>HTTP HTTPS</param-value>
  </init-param>
</servlet>

<servlet-mapping>
  <servlet-name>user</servlet-name>
  <url-pattern>/user/*</url-pattern>
</servlet-mapping>

<!-- admin servlet -->
<servlet>
  <servlet-name>admin</servlet-name>
  <servlet-class>org.restlet.ext.servlet.ServerServlet</servlet-class>
  <init-param>
    <param-name>org.restlet.application</param-name>
    <param-value>com.myapp.server.resource.admin.AdminApplication</param-value>
  </init-param>
  <init-param>
    <param-name>org.restlet.clients</param-name>
    <param-value>HTTP HTTPS</param-value>
  </init-param>
</servlet>

<servlet-mapping>
  <servlet-name>admin</servlet-name>
  <url-pattern>/admin/*</url-pattern>
</servlet-mapping>

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