基本上使用68000的组装语言,以张贴地址登记簿:
(A0)+
示例示例示例示例
MOVE (A0)+,D0
这将移动到 D0
的值, 以 A0
的地址表示, 1 还会递增 A0
。
考虑到(A0)
是 A0
指指的值,如果后加分语法是:
(A0+)
或者我错过了什么?
基本上使用68000的组装语言,以张贴地址登记簿:
(A0)+
示例示例示例示例
MOVE (A0)+,D0
这将移动到 D0
的值, 以 A0
的地址表示, 1 还会递增 A0
。
考虑到(A0)
是 A0
指指的值,如果后加分语法是:
(A0+)
或者我错过了什么?
MOVE.L (A1)+,D0 ; increments A1 by 4, because it is long operation
; and 4 is size of long
I think that current postincrement syntax points at this feature, while
(A1+)
more suggests that A1 incremens by one always.
http://en.wikibooks.org/wiki/68000_Assembly#Indent_addressing_ with_postincrement” rel=“no follow”>间接处理后写
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