Question

我需要检查SMTP服务器的超时，但我的套接字刚刚关闭。我做错了什么？这是我的测试：

#!/usr/bin/python
import smtplib
import time
import datetime
import socket
socket.setdefaulttimeout(1800)


now = time.time()
server = smtplib.SMTP()
server.set_debuglevel(1)
server.connect( mx.foo.bar , 25 )
(code,resp) = server.docmd( NOOP )
then = time.time()

print then-now

让我们希望这能奏效。

Answer 1

嗯，我还没有找到任何方法来保持smtplib打开的smtp连接。

But, if you want to reuse a connection without closing (yes, opening a connection takes time, 2-3 secs), you can test the connection first. To do this, issue a NOOP command and test for status == 250. If not, then you can open a connection and send out your mail. And you can choose to not quit() the connection until you are done.

import smtplib

def create_conn():
    conn = smtplib.SMTP( smtp.gmail.com , 587)
    ...
    return conn

def is_connected(conn):
    try:
        status = conn.noop()[0]
    except:  # smtplib.SMTPServerDisconnected
        status = -1
    return True if status == 250 else False

Answer 2

你确定要断开连接吗？当我在postfix服务器上运行上述代码时，我得到：

connect: ( server ,  25 )
connect: ( ip.address , 25)
reply:  220 server ESMTP Postfix
 
reply: retcode (220); Msg: nserver ESMTP Postfix
connect: server ESMTP Postfix
send:  NOOP
 
reply:  250 2.0.0 Ok
 
reply: retcode (250); Msg: 2.0.0 Ok
0.0531799793243

docmd不阻止，服务器响应，程序退出。因此，当程序退出时，我会断开连接。

如果我打开一个python命令行并执行以下操作：

>> import smtplib
>> server = smtplib.SMTP()
>> server.connect( server )
>> server.docmd( NOOP )
(250,  2.0.0 Ok )
>> ## let it sit for 5 minutes
>> server.docmd( NOOP )
(421,  4.4.2 server Error: timeout exceeded )

我的日志证实了这一点：

Oct 20 10:45:35 [postfix/smtpd] connect from unknown[ip.address]
Oct 20 10:50:10 [postfix/smtpd] timeout after NOOP from unknown[ip.address]

Answer 3

检查您的邮件服务器设置-他们可能正在切断连接。

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