我刚刚开始在露普洛宁和我刚刚注意到,一些冰川,如冰川融(......)或冰川(......)等,只接受Buffer物体的数据,而其他物体,如冰川-TexvOES(OES)、冰川-Paraifiv(O)也接受浮游。
为什么如此?
基本区别是,对冰川和冰川层功能的投入没有被利用,只有在采用冰川法(例如,冰川、冰川等)的情况下才能使用。
Since the arrays are not used right away, you need to keep the pointer to the array sent to these functions around long enough for the draw routines to access it. The data has to be on the native heap, otherwise the garbage collector could move the underlying native pointer even if it the data is not deleted. In order to get a pointer on the native heap, you need to wrap the data inside the Buffer objects.
类似冰川层的功能使用你穿透的阵列中的数值,因此,不存在从所谓的功能中移出点的担忧,也不必让这些点落在本土的肩上。
如果你使用来自本地法典的冰川和朋友,那么你必须把电线放在周围,直到你把冰川功能称作光彩之后。 从本地法典来看,你有好处,即点人不需要在物体上包装,但是,你不得不以人工方式管理任何肥皂分配。
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