Question

windows xp, gnu grep from http://gnuwin32.sourceforge.net/packages/grep.htm

I have file with line breaks:

test 
  123

I try to use gnu grep for finding this file by regexp pattern "test.* *.*12"

grep -G "test.*
*.*12" C:myfile_with_linebreaks.txt

但没有成功。

哪些参数或分类模式需要用来找到与线距相距的线索?

Answer 1

I often use [^] (every character but NUL), since most strings don t contain the NUL character. Otherwise, I assemble a character group that includes . and :

grep -G "test[.
]*12" C:

相反,如果你想要在测试与123之间打一个线,那么我就使用无盖的<代码>*操作者:

grep -G "test.*?
.*?12" C:

<代码>? 问讯号在*的操作者将限制该操作员。如果没有<代码>?,它将继续运行,直至其找到最后的对应数据;?,它将在下一个匹配时停止。

Also, it might be that you explicitly need to enable POSIX extended regular expressions, with the -E switch:

grep -E "test.*?
.*?12" C:

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