Question

I m writing a q script that loads a db in a particular path and does some processing on it. The location of the db is currently hardcoded in the script, but I want to pass the db path as an argument and get it to load from the path in the variable.

Currently it looks like this:

q) l /path/to/dbDir        #Works

I figured out that .Q.l should let us do this using a variable, so I tried using the following in the script,

dbPath:`$.z.x 0
.Q.l hsym dbPath            #Fails

When running with argument /path/to/dbDir, the script always fails with some unreadable stuff and:

 :/path/to/dbDir: No such file or directory

Could someone please help?

Answer 1

.Q.l is synonymous with l which only takes a single argument, which is not an hsym but a file or directory name.

Incidentally the unreadable stuff was the function definition, followed by a type error (as it was not expecting an hsym)

Answer 2

x ... is always equivalent to system"x ...", which is the general solution to the "how do i pass a variable to a command question

in your case, you want

system"l ",.z.x 0

(btw, i don t think .Q.l is involved in l of code, only of data, so don t try to use it to load extra .q files)

Answer 3

Okay, it seems to work when we try .Q.l without the hsym like this:

dbPath:`$.z.x 0
.Q.l dbPath

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