我在3D引擎中安装照明设备,发现我计算照明的方法有缺陷。在混合遮光镜中,我得到分散的颜色和照明计算。
return diffuseColor * (diffuseLight + ambient);
As far as I can tell, this is the standard way of doing things. But, for example, what if the color is 0,1,0, and the light is 1,0,0. (Ignore ambient in this example) The result would be 0,0,0. But in real life, if I get a pure green bit of paper, and shine a tinted red light onto it, it should turn out yellow. Or at least not black.
其他游戏如何解决这个问题?
A green paper will absorb red light and appear black, not yellow. Addition means you shine a white paper with red and green light. Then the paper appears yellow.
http://www.physics.wisc.edu/museum/Exhibits-2/Light_Optics/ColorObj/Color_index.html
它应该是(对于每个RGB组成部分)
return (diffuseColor * diffuseLight) + ambient;
环境组件是固定的,在所有其他照明计算完成后添加,不取决于光线方向或观测方向。
正如Julio所说,绿纸在红灯下将显得黑色。
当某物看起来绿色时,它就是因为它吸收了光谱中的所有其他颜色,而左边的颜色(如绿色)被反射。如果你在它上照亮红灯,没有绿色可以被反射。
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