Question

Following this post, I defined a macro inside a function:

macro Name(arg)
    string(arg)
end

function myfunc(df)
    @Name df
end

tf = 3
myfunc(tf)

What I want is:

tf

But what I actually got is

df

Is there a way to achieve this?

Thanks

Answer 1

The function takes arguments by value (an integer here), so the name tf of the variable passed is not seen by the function body, only 3. Inside the function, df is what the macro sees, not the variable that supplied 3 to the function. You would have to put the macro call in as an argument:

macro Name(arg)
    string(arg)
end

function myfunc(df, name = @Name tf)
    println(df)
    println(name)
    println(@Name df)
end

tf = 3

myfunc(tf)
println()
myfunc(tf, @Name foo)

Result:

3       
tf
df

3
foo
df

友情链接